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 A Number 
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Joined: Tue May 30, 2006 10:42 am
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Post  A Number
Puzzle:

A number when divided by 3 gives a remainder of 1; when divided by 4, gives a remainder of 2; when divided by 5, gives a remainder of 3; and when divided by 6, gives a remainder of 4. Find the smallest such number.


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Solution:

The number is 58.

LCM of 3, 4, 5 and 6 is 60. So these numbers when divides 60 gives remainder 0. Now to get the remainder 1, 2, 3 and 4 respectively, the number should be 2 (3-1 ; 4-2 ; 5-3 ; 6-4 ) short of 60.


Wed Feb 06, 2008 11:39 am
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Post  Re: A Number
well done .


Wed Apr 23, 2008 11:07 pm
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Post  Re: A Number
These kind of questions we get in entrance exams.

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Man is least himself when he talks in his own person. Give him a mask, and he will tell you the truth.


Tue May 13, 2008 1:38 am
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